Say I have: a = np.array([[2, 4], [6, 8]]) b = np.array([[1, 3], [1, 5]]) I want to get to: c = np.array([[20,32], [28, 44]]) where
Solution 1:
You can use np.dot
-
b.dot(a).T
Alternatively, using np.einsum
(for the kicks maybe) -
np.einsum('ij,ki->jk',a,b)
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