Initialize Empty Matrix In Python
Solution 1:
You could use a nested list comprehension:
# size of matrix n x mmatrix = [ [ 0 for i in range(n) ] for j in range(m) ]
Solution 2:
If you are using numpy
arrays, you initialize to 0, by specifying the expected matrix size:
import numpy as np
d = np.zeros((2,3))
>>> d
[[ 0. 0. 0.]
[ 0. 0. 0.]]
This would be the equivalent of MATLAB 's:
d = zeros(2,3);
You can also initialize an empty array, again using the expected dimensions/size
d = np.empty((2,3))
If you are not using numpy, the closest somewhat equivalent to MATLAB's d = []
(i.e., a zero-size matrix) would be using an empty list and then
append values (for filling a vector)
d = []
d.append(0)
d.append(1)
>>> d
[0, 1]
or append lists (for filling a matrix row or column):
d = []
d.append(range(0,2))
d.append(range(2,4))
>>> d
[[0, 1], [2, 3]]
See also:
NumPy array initialization (fill with identical values) (SO)
Solution 3:
What about initializing a list, populating it, then converting to an array.
demod4 = []
Or, you could just populate at initialization using a list comprehension
demod4 = [[func(i, j)for j in range(M)] for i in range(N)]
Or, you could initialize an array of all zeros if you know the size of the array ahead of time.
demod4 = [[0for j in range(M)] for i in range(N)]
or
demod4 = [[0 for i in range(M)]*N]
Or try using numpy
.
import numpy as np
N, M = 100, 5000
np.zeros((N, M))
Solution 4:
To init matrix with M rows and N columns you can use following pattern:
M = 3N = 2matrix = [[0] * N for _ in range(M)]
Solution 5:
If you want to initialize the matrix with 0s then use the below code
# for m*n matrixmatrix = [[0] * m for i in range(n)]
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