Iterating Over A Range Of Rows Using Ws.iter_rows In The Optimised Reader Of Openpyxl
Solution 1:
The simplest solution with a lower bound would be something like this:
# Your code:from openpyxl import load_workbook
filename = 'file_path'
wb = load_workbook(filename, use_iterators=True)
ws = wb.get_sheet_by_name('LOG')
# Solution 1:for row in ws.iter_rows(row_offset=1):
# code to execute per row...
Here another way to execute what you describe, with the enumerate
function:
# Solution 2:
start, stop = 1, 100# This will allow you to set a lower and upper limitforindex, row in enumerate(ws.iter_rows()):
if start < index < stop:
# code to execute per row...
The index variable keeps count of what row you are on, so it can be used in place of range or xrange. This method is pretty straightforward and works with iterators unlike range or slicing, and can be used with just the lower bound too, if desired. Cheers!
Solution 2:
From the documentation:
Note: When a worksheet is created in memory, it contains no cells. They are created when first accessed. This way we don’t create objects that would never be accessed, thus reducing the memory footprint.
Warning: Because of this feature, scrolling through cells instead of accessing them directly will create them all in memory, even if you don’t assign them a value. Something like
>>>for i in xrange(0,100):...for j in xrange(0,100):... ws.cell(row = i, column = j)
will create 100x100 cells in memory, for nothing.
However, there is a way to clean all those unwanted cells, we’ll see that later.
I think accessing the columns or rows properties will cause many cells to have to be loaded into memory. I would suggest only trying to directly access the cells you need.
eg.
col_name = 'A'
start_row = 1
end_row = 99
range_expr = "{col}{start_row}:{col}{end_row}".format(
col=col_name, start_row=start_row, end_row=end_row)
for (time_cell,) in ws.iter_rows(range_string=range_expr):
print time_cell.value.hour
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