Sort List Of Dictionaries Based On Values Where Keys Have Different Names

I have a list of dictionaries which look like the following: my_list = [ {'1200' : [10, 'A']}, {'1000' : [24, 'C']}, {'9564' : [6, 'D']}, ]

Solution 1:

sorted(my_list,key=lambda x: list(x.values())[0][0])
Out[114]: [{'9564': [6, 'D']}, {'1200': [10, 'A']}, {'1000': [24, 'C']}]

Solution 2:

You can use values() to access the dict elements:

sorted(my_list, key=lambda x: x.values()[0][0])

Output:

[
  {'9564': [6, 'D']},
  {'1200': [10, 'A']},
  {'1000': [24, 'C']}
]

This assumes that each entry contains a list with at least one element.

EDIT FOR PYTHON 3

As @cᴏʟᴅsᴘᴇᴇᴅ points out, values() does not return a list in python3, so you'll have to do:

sorted(my_list, key=lambda x: list(x.values()[0])[0])