Python Zeep: Send Un-escaped Xml As Content

I think what I am trying to do is pretty much like github issue in zeep repo --- but sadly there is no response to this issue yet. I researched suds and installed and tried -- did

Solution 1:

You can use a Plugin for editing the xml as a plain string. I used this plugin for keeping the characters '<' and '>' in a CDATA element.

from xml import etree
from zeep import Plugin

classmy_plugin(Plugin):

    defegress(self, envelope, http_headers, operation, binding_options):
        xml_string = etree.ElementTree.tostring(envelope)
        xml_string = xml_string.replace("&lt;", "<")
        xml_string = xml_string.replace("&gt;", ">")
        parser = etree.ElementTree.XMLParser(strip_cdata=False)
        new_envelope = etree.ElementTree.XML(xml_string, parser=parser)
        return new_envelope, http_headers

Then just import the plugin on the client:

client = Client(wsdl='url', transport=transport, plugins=[my_plugin()])

Take a look at the docs: http://docs.python-zeep.org/en/master/plugins.html

Solution 2:

On Python 3.9, @David Ortiz answer didn't work for me, maybe something has changed. The etree_to_string was failing to convert the XML to string.

What worked for me, instead of a plugin, I created a custom transport, that replaced the stripped tags with the correct characters, just like the David's code, before the post was sent.

import zeep
from zeep.transports import Transport
from xml.etree import ElementTree

classCustomTransport(Transport):  
    defpost_xml(self, address, envelope, headers):  
        message = ElementTree.tostring(envelope, encoding="unicode")  
        message = message.replace("&lt;", "<")  
        message = message.replace("&gt;", ">")  
        return self.post(address, message, headers)  


client = zeep.Client('wsdl_url', transport=CustomTransport())